(x+5.5)^2=10/4

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Solution for (x+5.5)^2=10/4 equation: 


x in (-oo:+oo)

(x+5.5)^2 = 10/4 // - 10/4

(x+5.5)^2-(10/4) = 0

(x+5.5)^2-5/2 = 0

(2*(x+5.5)^2)/2-5/2 = 0

2*(x+5.5)^2-5 = 0

2*x^2+22*x+55.5 = 0

2*x^2+22*x+55.5 = 0

2*x^2+22*x+55.5 = 0

DELTA = 22^2-(2*4*55.5)

DELTA = 40

DELTA > 0

x = (40^(1/2)-22)/(2*2) or x = (-40^(1/2)-22)/(2*2)

x = (2*10^(1/2)-22)/4 or x = (-2*10^(1/2)-22)/4

(x-((-2*10^(1/2)-22)/4))*(x-((2*10^(1/2)-22)/4)) = 0

((x-((-2*10^(1/2)-22)/4))*(x-((2*10^(1/2)-22)/4)))/2 = 0

((x-((-2*10^(1/2)-22)/4))*(x-((2*10^(1/2)-22)/4)))/2 = 0 // * 2

(x-((-2*10^(1/2)-22)/4))*(x-((2*10^(1/2)-22)/4)) = 0

( x-((-2*10^(1/2)-22)/4) )

x-((-2*10^(1/2)-22)/4) = 0 // + (-2*10^(1/2)-22)/4

x = (-2*10^(1/2)-22)/4

( x-((2*10^(1/2)-22)/4) )

x-((2*10^(1/2)-22)/4) = 0 // + (2*10^(1/2)-22)/4

x = (2*10^(1/2)-22)/4

x in { (-2*10^(1/2)-22)/4, (2*10^(1/2)-22)/4 }

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